1) При t = π/3:
sin(π/3) = √3/2
cos(π/3) = 1/2
2) При t = 5π/6:
sin(5π/6) = 1/2
cos(5π/6) = -√3/2
3) При t = 3π/2:
sin(3π/2) = -1
cos(3π/2) = 0
4) При t = -3π/4:
sin(-3π/4) = -√2/2
cos(-3π/4) = -√2/2
Таким образом, ответы на вопрос:
1) sin(π/3) = √3/2, cos(π/3) = 1/2
2) sin(5π/6) = 1/2, cos(5π/6) = -√3/2
3) sin(3π/2) = -1, cos(3π/2) = 0
4) sin(-3π/4) = -√2/2, cos(-3π/4) = -√2/2.